php - How can I make a custom exception object evaluate to false in an if condition? -

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I was just thinking that if I make my object wrong, the reason for this is that I create a custom exception class I am here. I would like to be able to do something on the lines of 

  class dog {public function lookAround () (see dog ()) {layer of bark;} and {return sit;}} public Function seeDog () {If (object == dog) {return "hoarse";} and {return Dog_Exception (no_see);}}}

I think this is a terrible silly example However, the issue is that as the object, if (see dog ()) test string "hoarse" and dog_exception both To evaluate true for the object, if possible, to evaluate the dog_exception to false , if if In such a situation, I will not have to do this like this, for example, create a code such as type (seedog) == dog_exception) etc. I suspect that this is possible, but any help would be great thanks!

Why are you refusing an exception? Do not you want to throw it?


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