python - Boolean evaluation in a lambda -

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Just tooling around for your own entertainment, and I want to use lambda, because I think so. Can I change this function with lambda? DEF isodd (number): if (number% 2 == 0): Returned wrong other: Back right

Primary, yes. But I am interested to know ...

And if you do not actually need a function lambda Without it, you can also change it :) 

  (number% 2! = 0)

The self is an expression that evaluates for right or wrong is. Or even normal, 

  bool (number% 2)

which you can do so simple: 

  If number% 2: print "Odd!" Other: Print "Even!"

But if it is readable or is probably not in view of the viewer.


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