python - How to return an alternate column element from the intersect command? -
I am currently using the following code to get the intersection date column of two sets of financial data. Intersect the difference in the interval of the mortgage gap (seq1, seq2): res = [] # in the seq1 for start xq: # in the date, the date, o, h, l, cl
# Scan Seq1 if x in seq2: # normal item? Res.append (x) Returns x = intersect (seta [, 0], setb [, 0]) # Mixed type print x
The problem is that only the column for which it Both, i.e., found the intersection of the date column. I want to return it to a different column ARAC, in any way, including the CLS values of each set ... i.e. if the date is both the same then 2X1 array will return to two similar SLS columns. any idea? Thank you.
How is it:
def intersect (seq1, seq2) : If CEC 1 [0] == CEC 2 [0]: # Return of the date column return (Ceik 1 [4], Seek 2 [4]) # Return with 2-Tulle CLS value
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