regex - Using map() to get number of times list elements exist in a string in Python -
How often am I trying to get every item in a string in Python in a list:
< Definition (X, Paragraph) Map (tester, ['banana', 'lawnbeberry', 'passion fruit'])returns [2, 0, 0]
What I have to do but extend it, so I can feed the paragraph value in the map ( ) Function. Now, the tester () function has a hard paragraph, is there any way to do this (maybe make an en-long list of paragraph values)? Any other ideas here?
Keep in mind that at any given time in the future, one of the array values will be weighing - so instead of keeping the prices in the list, all need to keep together. / P>
Update: Article will often be 20K and the list will often have 200+ members. My thinking is that the map runs in parallel - so it will be more efficient than any serial methods.
There is a reaction to the movement of targets ("I probably need reazes because I have a near future Word delimiter will be required "):
This method parses text to get a list of all times" word ". Each word is seen in a dictionary of the target words, and if it is a target word that is counted. The time taken is o (p) + o (t) where p is the paragraph size and t is the number of words. All other solutions (except currently accepted solutions) are O (PT) except my ego-corrosive solution. (In the target, 0) targets in goals (word_regex) in re.findall (define the target, paragraph, word_reggets = r "\ w +"): match = dict Paragraph): If the word in Milan: match [word] = 1 return [matching for goal [target] in target] def counts_iter (target, paragraph, word_reg x = r "\ w +"): target = target ( To target in target 0)) (Matchbox in redfound) (word_regex, paragraph): word = matchobj.group () if the word matches: Target [word] + = 1 Goal [Goal] Goal for Goals in Goals] Finder Edition is a Storman - it is much slower than finder version.
Here is an approved solution that is expressed in standardized form and the word is enlarged with the delimiter:
def current accepted_section_edirect (target, paragraph): def tes ter Return f (x): return f (x): return lane (re.findall (r "\ b" + x + r "\ b", s)) return f return map (tester (paragraph), target) which falls into the water when it is closed and can be reduced to:
# Acceptance: # In the same form, One of the benchmark works of hughdbrown (target currently_accepted_solution_augmented_without_extra_closure, paragraph): Def tester (x): return lane (refundle (r "\ b" + + + r "b", paragraph)) return map (tester, target ) All changes to the current accepted solution are o (PT). Contrary to the currently accepted solution, regex search with term delimiter is not a simple paragraph.find (target) . Again the engine does not use "sharp search" in this case, because this change fron very slow.
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