xml - How to assert for each child one element is present or not -

- 

  & lt; क्लिनिकल डॉक्यूमेंट & gt; & LT; प्रविष्टि & gt; & LT; substaceAdministration & gt; & LT; effectiveTime & gt; & lt; / effectiveTime & gt; & Lt; / substaceAdministration & gt; & Lt; / प्रविष्टि & gt; & LT; प्रविष्टि & gt; & LT; substaceAdministration & gt; & LT; effectiveTime & gt; & lt; / effectiveTime & gt; & Lt; / substaceAdministration & gt; & Lt; / प्रविष्टि & gt; & LT; प्रविष्टि & gt; & LT; substaceAdministration & gt; & Lt; / substaceAdministration & gt; & Lt; / प्रविष्टि & gt; & Lt; / ClinicalDocument & gt;

मुझे प्रत्येक प्रविष्टि / सबसाइट के लिए जबरदस्ती करना होगा। प्रशासन प्रभावी है समय तत्व मौजूद है या नहीं।

मैंने इस अभिव्यक्ति के साथ कोशिश की है 

  & Lt; xsl: जब परीक्षण = "गिनती (क्लीनिकल डॉक्यूमेंट / एंट्री / पदार्थ प्रशासन / प्रभावी समय) = 1" / & gt;

मैं इस आवश्यकता को पूरा करने के लिए मेरी XPath अभिव्यक्ति को बदलने के तरीके के बारे में सलाह चाहता हूं।

बाल तत्वों के सभी उदाहरणों को गिनने की कोशिश करने की बजाय, आपको सभी उदाहरणों को बिना बाल तत्वों को गिनना चाहिए (इसके लिए स्वरूपण के बारे में क्षमा करना, यह बहुत लंबा है): 

  & lt; xsl: जब परीक्षण = "गिनती (क्लीनिकल डॉक्यूमेंट / एंट्री / पदार्थ प्रशासन [नहीं (प्रभावी समय)]) = 0" & gt; & Lt;! - सही है जब सभी पदार्थ प्रशासन तत्वों में एक प्रभावी समय बच्चे - & gt; & Lt; / XSL: जब & gt;

आप प्रत्येक चेक के लिए प्रत्येक पाश या एक टेम्प्लेट में प्रति-तत्व प्रशासन आधार पर यह जांच भी कर सकते हैं: 

  & lt; ! - वर्तमान नोड का मानना ​​है कि पदार्थ प्रशासन - & gt; & Lt; xsl: if test = "गणना (प्रभावी समय) = 1" & gt; & Lt;! - सही है जब वहाँ एक और केवल एक प्रभावी समय बच्चे - & gt; & Lt; / XSL: यदि & gt;

Comments

Post a Comment

Popular posts from this blog

c# - ListView onScroll event -

-
I am programming a simple C # application, and I need a Scallow event on the list view. So I inherited the original ListView class created in ListviewEx witch. I found out how to locate the scroll message from WinAPI and I modified the WndProc method. Now I have this WndProc: protected override zero WndProc (Ref message message) {base.WndProc (Ref I); If (m.msg == WM_VSCROLL) {onScroll (This, New EventArgs ()); }} But the problem is, I do not know how to know about scrolling information. This data should be in wParam, but there is a LOWORD macro ++ like in C in C # and I switch to find the criteria like SB_ below, SB_ENDSCROLL, SB_PAGEUP etc. there any way Need to change the LOWORD macro from C #? Or any other way to find the necessary parameters about scrolling? You can define the WParam constants as the following: Private const int WM_HSCROLL = 0x114; Private Constant WM_VSCROLL = 0x115; Private contact int SBHOZZ = 0; Private Consultant SB_VERT = 1; Private Con...
Read more

PHP - get image from byte array -

-
I am trying to create a back-end for my mobile application. I am sending the content of an image in the body of the HTTP request (output stream) as a byte array, I want to read this stream of bytes in PHP scripts and take back an image. Can anyone tell me how can I do this? Thank you. You can obtain the request body $ body = Reading from file_get_contents ('php: // input'); What you do with that data Depending on you, you can write the data in a file as you mentioned that this is image data, you can drop the data into the object can do. Another option is to use and load the image.
Read more

Linux Terminal Problem with Non-Canonical Terminal I/O app -

-
I have a small app written in C to run on Linux. Part of the app accepts user-input from keyboard , And it uses non-canonical terminal mode so that it can respond to each keystroke. The section of the code that accepts input is a simple task that is called repeatedly in the loop: char get_input () {char C = 0; Int res = reading (input_tamille, & amp; c, 1); If (RSS == 0) 0 returns; If (res == -1) {/ * snip error handling * /} return c; } It reads a letter from the terminal if there is no input within a given time limit, (c_cc [VTIME] value in the vocabulary structure), read () 0 And get_input () is called again It all works very well, I have recently discovered that if you run this app in a terminal window, and then the app Close the terminal window without ending, the app will not exit Received, but CPU intensive launches into an infinite loop, where the read () returns 0 without waiting continued. So how can I get out of the apple if it runs from the terminal win...
Read more