PHP eval error when assigning value to variable -

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My CMS (modules are not meant for convenience) which allows people to view pages, comments, forum posts, blog posts, etc ...): 

  if (isset $ _GET ["m"])) {// Is the module present and active, and is this a function called the view? If (isset ($ modules_exists [$ _ GET ["m"]]) & amp; amp; amp; method_exists ($ _GET ["m"], "see")) / / yop {// load view (Should be an array) eval ("$ modules_view =". $ _ Get ["m"]. :: :: view (); "); if (! Is_array ($ module_view)) // is not an array :( {error :: e500module ($ _gET ["m"], $ _SERVER ["REQUEST_URI"]);}} else // If not, display error {Now I get these errors when parsing the page:  
  notice: undefined variable: c: \ wamp \ www \ system \ start.php in module_view parse error on line 34 : Parse error C: \ wamp \ www \ system \ start.php (34): eval () line '1 code on notice: undefined variable: in module_view C: \ wamp \ www \ system \ start.php on line 35   ");  
 
 instead of: 
 
  eval (" $ Module_view = ". $ _ GET [" m "]. :: :: view ); ");  
 
 I have not found any errors, but only the array is printed. 
 
 
 
 
 
 
 
 
 
 
 
 
 
 You should never make eval of any kind here is the right way to do this: 
 
  $ class = $ _GET [" Me "]; $ Modules_view = $ square :: view ();  
 
 But here too, you should have an array and check that $ square is an authorized module before executing any code, because it does not trust user input and user input Can be done: 
 
  $ class = $ _GET ["me"]; If (! In_array ($ square, $ authorized_modules)) {header ("HTTP / 1.1 404 not found"); // Always 404 is good to send in these cases, so search engine URL will not die ("Content not found"); } $ Module_view = $ class :: view ();  
 
 Just you know, your error is because you have to save your variable eval: 
 
  eval ("\ $ module_view =". $ _GET [ "M"] ":: visible ();".); It is evaluated before  
 
 or after eval () is given in the form of a string.

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