google app engine - How to refactor this Python code? -

- 

  वर्ग मेनपेज (webapp.RequestHandler): डीईएफ (स्वयं) प्राप्त करें: user = users.get_current_user () tasks_query = टास्क.ऑल () कार्यों = कार्य_क्वैरी.फेट (1000) यदि उपयोगकर्ता: url = users.create_logout_url (स्वयं। अनुरोध) अन्य: url = users.create_login_url (self.request.uri) template_values ​​= {'कार्य': कार्य , 'Url': url} पथ = os.path.join (os.path.dirname (__ फ़ाइल__), 'index.html') self.response.out.write (टेम्पलेट। रेंडर (पथ, टेम्पलेट_विभिन्न)) श्रेणी गैजेट ( Webapp.RequestHandler): def (स्वयं) प्राप्त करें: user = users.get_current_user () tasks_query = Task.all () कार्यों = tasks_query.fetch (1000) अगर उपयोगकर्ता: url = users.create_logout_url (self.request.uri) अन्य: Url = users.create_login_url (self.request.uri) template_values ​​= {'कार्य': कार्य, 'url': url} path = os.path.join (os.path.dirname (__ फ़ाइल__), 'गैजेट। Xml') self.response.out.wr आईटीई (टेम्पलेट। रेंडर (पथ, टेम्पलेट_मूल्य))

वास्तव में यह आपकी क्या निर्भर करता है भविष्य में दो वर्गों के बीच सामान्य होने की उम्मीद है रिफैक्टरिंग का उद्देश्य आम अबाधियों की पहचान करना है, कोड की लाइनों की संख्या को कम करने के लिए नहीं।

उस ने कहा, मान लें कि दो अनुरोध केवल टेम्पलेट में ही भिन्न होंगे: 

  वर्ग टास्कलिस्ट पृष्ठ (webapp.RequestHandler): डीईएफ़ (स्वयं) प्राप्त करें: उपयोगकर्ता = users.get_current_user () tasks_query = Task.all () कार्यों = tasks_query.fetch (1000) यदि उपयोगकर्ता: url = users.create_logout_url (स्वयं। Request.uri) अन्य: url = users.create_login_url (self.request.uri) template_values ​​= {'कार्य': कार्य, 'url': url} path = os.path.join (os.path.dirname (__ फ़ाइल__), Self.template_name ()) self.response.out.write (template.render (path, template_values)) क्लास मेनपेज (टास्कलिस्ट पृष्ठ): def template_name (self): वापसी 'index.html' श्रेणी गैजेट (टास्कलिस्ट पृष्ठ): def template_name ( स्वयं): 'गैजेट.एक्सएमएल' वापस करें

Comments

Post a Comment

Popular posts from this blog

c# - ListView onScroll event -

-
I am programming a simple C # application, and I need a Scallow event on the list view. So I inherited the original ListView class created in ListviewEx witch. I found out how to locate the scroll message from WinAPI and I modified the WndProc method. Now I have this WndProc: protected override zero WndProc (Ref message message) {base.WndProc (Ref I); If (m.msg == WM_VSCROLL) {onScroll (This, New EventArgs ()); }} But the problem is, I do not know how to know about scrolling information. This data should be in wParam, but there is a LOWORD macro ++ like in C in C # and I switch to find the criteria like SB_ below, SB_ENDSCROLL, SB_PAGEUP etc. there any way Need to change the LOWORD macro from C #? Or any other way to find the necessary parameters about scrolling? You can define the WParam constants as the following: Private const int WM_HSCROLL = 0x114; Private Constant WM_VSCROLL = 0x115; Private contact int SBHOZZ = 0; Private Consultant SB_VERT = 1; Private Con...
Read more

PHP - get image from byte array -

-
I am trying to create a back-end for my mobile application. I am sending the content of an image in the body of the HTTP request (output stream) as a byte array, I want to read this stream of bytes in PHP scripts and take back an image. Can anyone tell me how can I do this? Thank you. You can obtain the request body $ body = Reading from file_get_contents ('php: // input'); What you do with that data Depending on you, you can write the data in a file as you mentioned that this is image data, you can drop the data into the object can do. Another option is to use and load the image.
Read more

Linux Terminal Problem with Non-Canonical Terminal I/O app -

-
I have a small app written in C to run on Linux. Part of the app accepts user-input from keyboard , And it uses non-canonical terminal mode so that it can respond to each keystroke. The section of the code that accepts input is a simple task that is called repeatedly in the loop: char get_input () {char C = 0; Int res = reading (input_tamille, & amp; c, 1); If (RSS == 0) 0 returns; If (res == -1) {/ * snip error handling * /} return c; } It reads a letter from the terminal if there is no input within a given time limit, (c_cc [VTIME] value in the vocabulary structure), read () 0 And get_input () is called again It all works very well, I have recently discovered that if you run this app in a terminal window, and then the app Close the terminal window without ending, the app will not exit Received, but CPU intensive launches into an infinite loop, where the read () returns 0 without waiting continued. So how can I get out of the apple if it runs from the terminal win...
Read more